A 51.7 kg box initially at rest is pushed 6.99 m along a rough, horizontal floor with a constant applied horizontal force of 84.1457 N. If the coefficient of friction between box and floor is 0.142, find the work done by the applied force. The acceleration of gravity is 9.8 m/s 2. Answer in units of J.

Question

Cherish Cooke

Physics

4 December, 18:04

A 51.7 kg box initially at rest is pushed 6.99 m along a rough, horizontal floor with a constant applied horizontal force of 84.1457 N. If the coefficient of friction between box and floor is 0.142, find the work done by the applied force. The acceleration of gravity is 9.8 m/s 2. Answer in units of J.

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Answers (1)

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Augustus Lloyd · Answer 1

Given Information:

Mass = 57.7 Kg

Horizontal distance = 6.99 m

Horizontal force = 84.1457 N

Coefficient of friction = 0.142

Required Information:

Work done = W = ?

Answer:

Work done = 588.178 Joules

Explanation:

The work done by the applied force is given by

W = Fx*d

Where Fx is the force applied in the horizontal direction and d is the distance the box covered horizontally after being pushed,

W = 84.1457*6.99

W = 588.178 Joules

Therefore, the work done by the applied force is 588.178 J