A (n) 19000 kg freight car is rolling along a track at 1.5 m/s. Calculate the time needed for a force of 2600 N to stop the car.

Answer: 10.96secs

Explanation:

According to newton's second law

Force = mass * acceleration

F = ma

F = m (v-u) / t

Cross multiplying we have

Ft = m (v-u)

t = m (v-u) / F

Given F = 2600N m = 19,000kg v = 1.5m/s u = 0m/s

Substituting this values in the formula for the time we have

t = 19000 (1.5-0) / 2600

t = 28,500/2600

t = 10.96secs