A long solenoid that has 810 turns uniformly distributed over a length of 0.380 m produces a magnetic field of magnitude 1.00 10-4 T at its center. What current is required in the windings for that to occur

Question

Trent Holmes

Physics

21 August, 01:52

A long solenoid that has 810 turns uniformly distributed over a length of 0.380 m produces a magnetic field of magnitude 1.00 10-4 T at its center. What current is required in the windings for that to occur

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Answers (1)

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Catherine · Answer 1

0.037 A

Explanation:

Magnetic field = B = 1.00 e-4 T

Length = L = 0.380 m

Number of turns = 810

B = μ₀ N I / L

⇒ Current = I = B L / μ₀ N = (1 e-4) (0.380) / (4π * 10⁻⁷) (810)

= 0.037 A = 37.3 mA