A ray of light in glass strikes a water-glass interface at an angle of incidence equal to one-half the critical angle for that interface. The index of refraction for water is 1.33, and for the glass it is 1.43. What angle does the refracted ray in the water make with the normal

There will not be any internal reflection. it will be only refraction

critical angle = θ

Sinθ = 1 / μg

μg = 1.43 / 1.33 =

Sinθ = 1.33 / 1.43

=.93

θ = 68.44

angle of incidence i = 68.44 / 2

= 34.22

Sin i / Sin r = μw = 1.33 / 1.43

=.93

sin 34.22 / sinθ₁ =.93, θ₁ is angle of refraction.

sinθ₁ = sin 34.22 /.93

=.5623 /.93

=.6047

θ₁ = 37 degree Ans