5. In order for an F-18 fighter jet to take off from an aircraft carrier, it needs to reach a

speed of 73 m/s by quickly accelerating down a 90 m long runway. If an F-18 starts its

takeoff from rest, what acceleration does the fighter jet undergo during takeoff?

Question

Katrina Leon

Physics

15 October, 09:46

5. In order for an F-18 fighter jet to take off from an aircraft carrier, it needs to reach a

speed of 73 m/s by quickly accelerating down a 90 m long runway. If an F-18 starts its

takeoff from rest, what acceleration does the fighter jet undergo during takeoff?

+1

Answers (1)

Know the Answer?

Arturo Rollins · Answer 1

a = 29.60 ms²

Explanation:

Given

V (f) = 73m/s

S = 90m

V (i) = 0m/s beacuse it takeoff from rest

a = ?

Formula

S = (V (f) ² - V (i) ²) / 2 a

So, put the values

2a (90) = ((73) ² - (0) ²)

180a = 5329

a = 5329/180

a = 29.60 ms²

5. In order for an F-18 fighter jet to take off from an aircraft carrier, it needs to reach aspeed of 73 m/s by quickly accelerating down a 90 m long runway. If an F-18 starts itstakeoff from rest, what acceleration does the fighter jet undergo during takeoff?

5. In order for an F-18 fighter jet to take off from an aircraft carrier, it needs to reach a

speed of 73 m/s by quickly accelerating down a 90 m long runway. If an F-18 starts its

takeoff from rest, what acceleration does the fighter jet undergo during takeoff?