Ask Question
25 June, 01:58

A proton moves at a speed of 1,140 m/s in a direction perpendicular to a magnetic field with a magnitude of 0.78 T. If the proton is replaced with an electron, how will the magnitude of the force change?

+1
Answers (1)
  1. 25 June, 02:05
    0
    1.42*10⁻¹⁶ N.

    Explanation:

    The force on a charge moving in a magnetic field is given as

    F = qBvsin∅ ... Equation 1

    Where F = Force on the charge, q = charge, B = Magnetic Field, v = speed, ∅ = angle between the magnetic field and the speed

    Given: B = 0.78 T, v = 1140 m/s, ∅ = 90° (Perpendicular) q = 1.60 * 10⁻¹⁹ C.

    Substitute into equation 1

    F = 0.78 (1140) (1.60 * 10⁻¹⁹) sin90°

    F = 1.42*10⁻¹⁶ N.

    Hence the force on the charge = 1.42*10⁻¹⁶ N.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A proton moves at a speed of 1,140 m/s in a direction perpendicular to a magnetic field with a magnitude of 0.78 T. If the proton is ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers