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29 March, 22:16

A daredevil is shot out of a cannon at 45.0° to the horizontal with an initial speed of 31.0 m/s. A net is positioned a horizontal distance of 48.5 m from the cannon. At what height above the cannon should the net be placed in order to catch the daredevil?

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Answers (2)
  1. 29 March, 22:56
    0
    24.5 m

    Explanation:

    First, find the time it takes for the daredevil to travel 48.5 m horizontally:

    x = x₀ + v₀ t + ½ at²

    (48.5 m) = (0 m) + (31.0 m/s cos 45.0°) t + ½ (0 m/s²) t²

    t = 2.21 s

    Next, find the vertical position reached at this time:

    y = y₀ + v₀ t + ½ at²

    y = (0 m) + (31.0 m/s sin 45.0°) (2.21 s) + ½ (-9.8 m/s²) (2.21 s) ²

    y = 24.5 m

    The net should be placed 24.5 meters above the cannon.
  2. 29 March, 23:16
    0
    s = vcos (x) t

    50 = 25cos (45) t

    cos (45) t = 2

    t = 2/cos (45) = 2sqrt (2)

    h = vsin (x) t + gt^2/2

    h = 25sin (45) * 2sqrt (2) - 4.9*8

    h = 10.8 metres
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