A 1200-kg car moving at 14 m/s collides completely inelastically with a 4500-kg truck at rest. Since the collision is completely inelastic, the car and the truck stick together and move as a single object after the collision. How fast do they move off after the collision?

Question

Tori

Physics

15 September, 15:19

A 1200-kg car moving at 14 m/s collides completely inelastically with a 4500-kg truck at rest. Since the collision is completely inelastic, the car and the truck stick together and move as a single object after the collision. How fast do they move off after the collision?

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Answers (1)

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Valerie Young · Answer 1

Answer:2.95 m/s

Explanation:

Moving car:

M1=1200kg

U1=14m/s

Car at rest:

M2=4500kg

U2=0

Their common velocity=v

M1xU1+M2xU2=V (M1+M2)

1200x14+4500x0=v (1200+4500)

16800+0=v (5700)

16800=5700v

Divide both sides by 5700

16800/5700=5700v/5700

2.95=v approximately

Their common velocity=2.95 approximately