A physics student tests the theory of projectile motion by leaping off a 225 meter tall building. She runs off the building horizontally at 12.5 m/s. How far away from the base of the building should she place the safety net?

Question

Julius

Physics

27 August, 01:47

A physics student tests the theory of projectile motion by leaping off a 225 meter tall building. She runs off the building horizontally at 12.5 m/s. How far away from the base of the building should she place the safety net?

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Sebastian Warren · Answer 1

In this item, we are given with the x-component of the velocity. The y-component is equal to 0 m/s. The time it takes for it to reach the volume can be related through the equation,

d = V₀t + 0.5gt²

Substituting the known values,

225 = (0 m/s) (t) + (0.5) (9.8) (t²)

Simplifying,

t = 6.776 s

To determine the distance of the student from the edge of the building, we multiply the x-component by the calculated time.

range = (12.5 m/s) (6.776 s)

range = 84.7 m

Answer: 84.7 m