A ladybug falls into small hole. it takes 8.6s for the ladybug to hit the bottom. how deep is the hole? (take g=9.81 m/s²)

Question

Deon

Physics

15 May, 17:38

A ladybug falls into small hole. it takes 8.6s for the ladybug to hit the bottom. how deep is the hole? (take g=9.81 m/s²)

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Answers (1)

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Lamont Wiggins · Answer 1

Length of hole (s) = 362.77 m (Approx)

Explanation:

Given:

Time taken to hit the bottom (t) = 8.6 s

Acceleration due to gravity (g) = 9.81 m/s²

Find:

Length of hole (s) = ?

Computation:

Initial velocity (u) = 0 m/s

S = ut + 1/2 (gt²)

S = (0) (8.6) + 1/2 (9.81) (8.6) (8.6)

S = 1/2 (9.81) (8.6) (8.6)

S = 1/2 (9.81) (8.6) (8.6)

S = 362.7738

Length of hole (s) = 362.77 m (Approx)