Ask Question
23 January, 20:53

If a ball is thrown into the air with a velocity of 36 ft/s, its height (in feet) after t seconds is given by y = 36t - 16t2. find the velocity when t = 1.

+2
Answers (1)
  1. 23 January, 21:03
    0
    Height (y) = 36t - 16t^2, where t = time in seconds (s).

    Our height (y) after 1s = 36 (1) - 16 (1) ^2

    y = 36 - 16 = 20 ft

    So it reached a height of 20 ft during that 1 second, which means that at that 1 second it had a velocity of 20ft/s, since v = d (distance) / t = 20ft/1s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “If a ball is thrown into the air with a velocity of 36 ft/s, its height (in feet) after t seconds is given by y = 36t - 16t2. find the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers