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15 December, 06:17

A skidder dragging of 520 kg walk-through forest at a constant speed of 3.5 m/s. If the skidder is applying a force of 1850 N what is the coefficient of friction between the log and the ground

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  1. 15 December, 06:40
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    The coefficient of friction between the log and the ground is, μₓ = 0.3630

    Explanation:

    Given data,

    The skidder dragging the mass, m = 520 kg

    The acceleration of the mass, a = 3.5 m/s

    The force applied by the skidder, Fₓ = 1850 N

    The kinetic frictional force is given by,

    Fₓ = μₓ η

    μₓ = Fₓ / η

    Where μₓ - the coefficient of the kinetic friction

    η is the normal force acting on the mass due to gravitational force.

    η = mg

    = 520 x 9.8

    = 5096 N

    Substituting the values in the above equation,

    μₓ = 1850 N / 5096 N

    = 0.3630

    Hence, the coefficient of friction between the log and the ground is, μₓ = 0.3630
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