A sprinkler sprays water out of a hose with a velocity of 6.3 m/s. if the sprinkler is aimed 25Â° above the ground, at what distance from the sprinkler does the water hit the ground? ignore air resistance and use 9.8 m/s2 for acceleration due to gravity.

Question

Guest

Physics

7 January, 11:44

A sprinkler sprays water out of a hose with a velocity of 6.3 m/s. if the sprinkler is aimed 25Â° above the ground, at what distance from the sprinkler does the water hit the ground? ignore air resistance and use 9.8 m/s2 for acceleration due to gravity.

+4

Answers (1)

Know the Answer?

Brice Atkinson · Answer 1

The step by step solution would be:

1. Look for the vertical component of spray, this is calculated by: (sin 25 degrees x 6.3) = 2.662 m/sec.

2. Then look for the time to max height = (v/g) = 2.662/9.8 = 0.272 sec.

3. Double the amount you got from 2; this is for time to reach the ground, = 0.544 sec.

4. Then compute for the horizontal V of spray = (cos 25 degrees x 6.3) = 5.710 m/sec.

5. So the horizontal distance = (5.710 x 0.544) = 3.106 meters.