Where is the center of gravity if the 9.00 kg mass of the barbell itself is taken into account?

The problem is missing some parts but nevertheless here is the answer:

Given:

1.7 m long barbell with 23 kg weight on the left and 34 in the right end.

Solution:

Calculating from the left side:

Center of gravity = ΣM/ΣW = [23*0 + 9 * (1.7/2) + 34*1.7]/[23+9+34]

Center of gravity =.992 m from the left end