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14 July, 12:03

A 282 kg motorcycle moves with the velocity of 4 m/s what is the kinetic energy

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  1. 14 July, 12:07
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    KE=1/2mv^2

    KE=1/2 (282) (4) ^2 or 282*16

    3512/2 = 1756

    So the answer is 1756 J.
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