Two particles, one with charge - 3.77 μC - 3.77 μC and one with charge 4.39 μC, 4.39 μC, are 4.34 cm 4.34 cm apart. What is the magnitude of the force that one particle exerts on the other?

the magnitude of the force that one particle exerts on the other is 79.08 N

Explanation:

given information:

q₁ = 3.77 μC = - 3.77 x 10⁻⁶ C

q₂ = 4.39 μC = 4.39 x 10⁻⁶ C

r = 4.34 cm = 4.34 x 10⁻² m

What is the magnitude of the force that one particle exerts on the other?

lFl = kq₁q₂/r²

= (9 x 10⁹) (3.77 x 10⁻⁶) (4.39 x 10⁻⁶) / (4.34 x 10⁻²) ²

= 79.08 N