If the torque required to loosen the nut that is holding a flat tire in a place on a car has a magnitude of 35 N•m what minimum force must be exerted by the mechanic at the end of a 27 cm long wrench to loosen the nut

129.63 N

Explanation:

Torque : This can be defined as a force that tend to rotate or twist a body. The S. I unit of torque is N. m. The expression of torque is given as,

T = F*d ... Equation 1

Where T = Torque on the car's nut. F = The minimum force exerted on the car, d = distance between the force and the nut.

make F the subject of the equation,

F = T/d ... Equation 2

Given: T = 35 N. m, d = 27 cm = 0.27 m.

Substitute into equation 2

F = 35/0.27

F = 129.63 N.

Hence the minimum force exerted by the mechanic to loosen the nut = 129.63 N

Answer: F = 130 N

Explanation: Solution:

Convert first 27 cm to m.

27 cm x 0.01 m / 1 cm = 0.27 m

Calculate the torque using T = Fd

Derive to find force F

F = T / d

= 35 N. m / 0.27 m

= 130 N