A car travelling at 20 m/s due north along the highway makes a right turn on to a side road that heads due east. It takes 50 s for the car to complete the turn. At the end of 50 s, the car has a speed of 15 m/s along the side road. Determine the magnitude of average acceleration over the 50 s interval.

Question

Andrew

Physics

30 September, 11:26

A car travelling at 20 m/s due north along the highway makes a right turn on to a side road that heads due east. It takes 50 s for the car to complete the turn. At the end of 50 s, the car has a speed of 15 m/s along the side road. Determine the magnitude of average acceleration over the 50 s interval.

+2

Answers (1)

Know the Answer?

Jaylin Walls · Answer 1

Answer: initial velocity: 20 m/s

time taken to complete the turn: 50s

final velocity: 15 m/s

average acceleration = final velocity-initial velocity/time taken - 0s (0 is taken here as there was no initial time)

= 15-20/50-0

= - 5/50 = - 0.1 ms^2