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15 July, 20:21

The leader of a bicycle race is traveling with a constant velocity of + 12.60 m/s and is 11.4 m ahead of the second-place cyclist. the second-place cyclist has a velocity of + 9.20 m/s and an acceleration of + 1.50 m/s2. how much time elapses before he catches the leader?

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  1. 15 July, 20:40
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    Let the time be t.

    so, In time t, distance travelled by 1st cyclist = 12.6 t

    distance travelled by 2nd cyclist = 9.2t + 0.5 (1.5) t^2

    Now, cyclist 1st is already 11.4 m ahead of 2nd cyclist.

    so, 9.2t + 0.5 (1.5) t^2 = 11.4 + 12.6t

    find t:

    t = 6.77 sec
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