A train moving at a constant speed on a surface inclined upward at 10.0° with the horizontal travels a distance of 400 meters in 5 seconds. Calculate the vertical velocity component of the train during this time period

Question

Megan Barr

Physics

27 May, 15:13

A train moving at a constant speed on a surface inclined upward at 10.0° with the horizontal travels a distance of 400 meters in 5 seconds. Calculate the vertical velocity component of the train during this time period

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Kolby Sheppard · Answer 1

If the velocity of the train is v=s/t, where s is the distance and t is time, then v=400/5=80m/s. To get the vertical component of the velocity we need to multiply the velocity v with a sin (α) : Vv=v*sin (α), where Vv is the vertical component of the velocity and α is the angle with the horizontal. So:

Vv=80*sin (10) = 80*0.1736=13.888 m/s.

So the vertical component of the velocity of the train is Vv=13.888 m/s.