A machinist is using a wrench to loosen a nut. The wrench is 25.0 {/rm cm} long, and he exerts a 17.0-{/rm N} force at the end of the handle at 37 ^/circ with the handle

What is the magnitude of the torque does the machinist exert about the center of the nut?

What is the direction of the torque in part (A).

What is the maximum torque he could exert with this force?

How should the force mentioned in part (C) be oriented?

Question

Natasha Tyler

Physics

25 November, 17:32

A machinist is using a wrench to loosen a nut. The wrench is 25.0 {/rm cm} long, and he exerts a 17.0-{/rm N} force at the end of the handle at 37 ^/circ with the handle

What is the magnitude of the torque does the machinist exert about the center of the nut?

What is the direction of the torque in part (A).

What is the maximum torque he could exert with this force?

How should the force mentioned in part (C) be oriented?

+3

Answers (1)

Know the Answer?

Antonio Cantrell · Answer 1

Torque = force * perpendicular distance from the axis of rotation

τ=force∗r where r is the perpendicular distance from the axis of rotation

direction is upwards

maximum torque can be applied if the direction of force is perpendicular to the axis of rotation