A set of data is collected for objects in an inelastic collision, as recorded in the table.

To identify the momentum of Object 1, you must multiply (A. elapsed time B. mass C. acceleration and (A. elapsed time B. applied force C. velocity) to find momentum.

Object 1 had a momentum of (A. 2.0 B. 4.0 C. 8.0) kg ∙ m/s before the collision. Object 2 had a momentum of (A. 0.0 B. 6.0 C. 8.0) kg ∙ m/s before the collision. The combined mass after the collision had a total momentum of. (A. 14.0 B. 10.0 C. 8.0)

M (kg) V (m/s) P (kg. m/s)

Object 1 2.0 4.0

Object 2 6.0 0

Object 3 8.0 1.0

Momentum = Mass x Velocity

In a collision, the Total Momentum of the system is always conserved (stays the same.) To find the total momentum of the system just add the momentum of all the objects together.

A body in motion has momentum. It is the product of mass and velocity.

To identify the momentum of object 1, we mus multiply B. mass and C. velocity.

Mass of object 1 is: 2.0 kg and velocity is 4.0 m/s

So, the momentum of the object 1 is:

P = m v

⇒ P = 2.0 kg * 4.0 m/s = 8.0 kg m/s

Thus, Object 1 had a momentum of C. 8.0 kg ∙ m/s before the collision.

Mass of Object 2: 6.0 kg

Velocity of object 2 = 0

Thus, Object 2 had a momentum of A. 0.0 kg. m/s before the collision.

Mass of object 3: 8.0 kg

velocity of object 3: 1.0 m/s

Momentum of object 3 before collision = 8.0 kg * 1.0 m/s = 8.0 kg. m/s

From law of conservation of momentum, initial momentum is equal to final momentum.

Initial momentum = (8 + 0 + 8) kg. m/s = 16.0 kg. m/s

Thus, the combined mass would have a total momentum = 16.0 kg. m/s after collision.

The combined mass (2+6+8 = 16 kg) would move with the velocity of:

v = P/m = (16.0 kg. m/s) / 16 kg = 1 m/s after collision.