A student hangs a weight on a newtonmeter. The energy currently stored in the spring in the newton meter is 0.045N. The student then increases the weight on the newtonmeter by 2N. If the spring constant is 400N/m what is the total extension of the spring?

5x10^-3

Explanation:

Hooke's Law states that the force needed to compress or extend a spring is directly proportional to the distance you stretch it.

Hooke's Law can be represented as

F = kx,

where F is the force

k is the spring constant

x is the extension of the material

Plug values in the equation

Step 1 find the original extension

0.045 = (400) x

x = 1.125x 10^-4 m d

Step 2 find the new extension

0.045+2 = 400 (x)

2.045 = 400x

x = 5.1125x10^-3

Step 3 subtract the new extension with original

Total extension of the spring = 5.1125x10^-3 - 1.125x 10^-4 m = 5x10^-3