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4 July, 19:40

Dave and sandy hartranft are frequent flyers with a particular airline. they often fly from city a to city b, a distance of 732732 miles. on one particular trip, they fly into the wind, and the flight takes 22 hours. the return trip, with the wind behind them, only takes 1 and one half1 1 2 hours. if the wind speed is the same on each trip, find the speed of the wind and find the speed of the plane in still air

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  1. 4 July, 20:00
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    Let the speed of the plane in still air = x

    and speed of wind = y

    Now from city A to B

    dIstance = speed * time

    732732 = (x - y) * 2 (1)

    From city B to A

    Distance = speed * time

    732732 = (x + y) * 1.5 (2)

    From (1) and (2)

    2x - 2y = 1.5x + 1.5y

    0.5x = 3.5y

    x = 7y

    If we plug in (1)

    732732 = (7y - y) * 2

    732732/12 = 12y/12

    y = 61061

    Since x = 7y

    = 427427 miles/hr

    Speed of still air plane is 427427 miles/hr

    Speed of wind = 61061miles/hr
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