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2 May, 10:39

A particle at rest undergoes an acceleration of 1.5 m/s 2 to the right and 3.7 m/s 2 up. what is its speed after 6.4 s? answer in units of m/s.

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  1. 2 May, 11:01
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    The resultant of the acceleration can be found using:

    a = √ (ax² + ay²)

    a = √ (1.5² + 3.7²)

    a = 3.99 m/s²

    v = u + at, u = 0

    v = 3.99 x 6.4

    v = 25.5 m/s
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