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30 March, 21:39

An object experiences an acceleration of - 6.8m/s^2. As a result, it accelerates from 54m/s to a complete stop. how much distance did it travel during that acceleration

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  1. 30 March, 22:53
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    210 m

    Explanation:

    Given:

    a = - 6.8 m/s²

    v₀ = 54 m/s

    v = 0 m/s

    Find: Δx

    v² = v₀² + 2aΔx

    (0 m/s) ² = (54 m/s) ² + 2 (-6.8 m/s²) Δx

    Δx ≈ 210 m
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