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1 March, 03:25

A quantity of a gas is an absolute pressure of 400 K PA in the absolute temperature of 110° Kelvin when the temperature of the gas is raised to 235° Kelvin what's the new pressure of the gas?

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  1. 1 March, 03:31
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    Given:

    P1 = 400 kPa

    T1 = 110 K

    T2 = 235K

    Required:

    P2

    Solution:

    Apply Gay-Lussac’s law where P/T = constant

    P1/T1 = P2/T2

    P2 = T2P1/T1

    P2 = (235K) (400kPa) / (110K)

    P2 = 855 kPa
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