A 70-kg person in a moving car stops during a car collision in a distance of 0.60m. the stopping force that the air bag exerts on the person is 8000N. name at least three physical quantities describing the person's motion that you can determine using this information, and then determine them.

The three quantities are: acceleration, initial velocity and time

1. Acceleration

We can find the acceleration using Newton's Second Law of Acceleration:

F = ma

(8,000 N) = (70 kg) (a)

Solving for a,

a = 114.286 m/s²

2. Initial Velocity

For this quantity, we use the equation for rectilinear motion at constant acceleration.

2ax = |v² - v₀²|

where

x is the distance

v is the final velocity

v₀ is the initial velocity

2 (114.286 m/s²) (0.60 m) = |0² - v₀²|

Solving for v₀,

v₀ = 11.71 m/s

3. Time

We can determine time fro the formula of acceleration:

a = |v - v₀|/t

114.286 m/s² = |0 - 11.71|/t

Solving for t,

t = 0.102 seconds