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21 April, 02:52

A pipe originally has a radius of 1.25m. It narrows down to a radius of 0.55m. If the original force in the big pipe is 72N, what is the force in the narrow part of the pipe?

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  1. 21 April, 03:09
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    Use direct proportionality: If 1.25 m = 72 N, then 0.55 m = y

    0.55 m * 72 = 39.6.

    39.6:1,25 gives you your answer which is 31.68 N.
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