Calculate delta g for the reaction if the partial pressures of the initial mixture are pcl5 =.0029 atm, pcl3 =.27 atm, and pcl2 =.40 atm

Question

Marquis

Physics

24 April, 21:03

Calculate delta g for the reaction if the partial pressures of the initial mixture are pcl5 =.0029 atm, pcl3 =.27 atm, and pcl2 =.40 atm

+1

Answers (1)

Know the Answer?

Titus Cochran · Answer 1

Answer: equation for the reaction is given below

PCL2+PCL3=PCL5

Where pcl2=0.40atm, pcl3=0.27atm

Pcl5=0.0029atm

Using ∆G=-RTin (PCL5/PCl2*PCL3)

Where R=8.314J/K/mol and T=298K

∆G=-8.314*298in (0.0029/0.40*.27)

∆G=8962.6J/mol