Two 3.3 g bullets are fired with speeds of 38.0 m/s and 83.7 m/s, respectively. a) What is the kinetic energy of the first bullet

Kinetic energy of the first bullet is 2.38 Joules

Explanation:

Kinetic energy is given by

Kinetic energy = 0.5 x Mass x Velocity²

Here mass and velocity is given we need to find kinetic energy.

Mass, m = 3.3 g = 3.3 x 10⁻³ kg

Velocity, v = 38.0 m/s

Substituting

Kinetic energy = 0.5 x Mass x Velocity²

Kinetic energy = 0.5 x 3.3 x 10⁻³ x 38.0²

Kinetic energy = 2.38 J

Kinetic energy of the first bullet is 2.38 Joules