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25 November, 23:35

14. A ball initially at rest rolls without slipping

an incline of height 'h'. What is the linear

speed of the ball when it rolls onto the

horizontal surface?

Solution:

+3
Answers (1)
  1. 26 November, 00:01
    0
    v = √ (10gh/7)

    Explanation:

    Initial gravitational energy = final rotational energy + kinetic energy

    PE = RE + KE

    mgh = ½ Iω² + ½ mv²

    For a solid sphere, I = ⅖ mr².

    For rolling without slipping, ω = v/r.

    mgh = ½ (⅖ mr²) (v/r) ² + ½ mv²

    mgh = ⅕ mv² + ½ mv²

    mgh = 7/10 mv²

    10/7 gh = v²

    v = √ (10gh/7)
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