A box, with a weight of mg = 25 N, is placed at the top of a ramp and released from rest. The ramp measures 4.70 meters horizontally and 3.00 meters vertically. The box accelerates down the incline, attaining a kinetic energy at the bottom of the ramp of 52.0 J. There is a force of kinetic friction acting on the box as it slides down the incline. How much work does the normal force do on the box as the box slides down the incline?

Question

Sidney Hickman

Physics

14 January, 06:23

A box, with a weight of mg = 25 N, is placed at the top of a ramp and released from rest. The ramp measures 4.70 meters horizontally and 3.00 meters vertically. The box accelerates down the incline, attaining a kinetic energy at the bottom of the ramp of 52.0 J. There is a force of kinetic friction acting on the box as it slides down the incline. How much work does the normal force do on the box as the box slides down the incline?

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Answers (1)

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Sara Whitney · Answer 1

the work done by the normal force will be zero

Explanation:

We have given the weight of the box mg = 25 KN

The box is released from the rest

It is also given that ramp measures 4.70 meters horizontally and 3 meters vertically

We have to find the work done by the normal force

Normal force and displacement will be perpendicular top each other

And we know that when force and displacement is perpendicular to each other then work done will be zero

So the work done by the normal force will be zero