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7 April, 18:04

A bimetallic strip consists of two 1-mm thick pieces of brass and steel bonded together. At 20 C, the strip is completely straight and has a length of 10 cm. At 30 C, the strip bends into a circular arc. What is the radius of curvature of this arc?

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  1. 7 April, 18:08
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    R = 16.67 m

    Explanation:

    Given:

    - Initial Temperature T_i = 20 C

    - Thickness of both strips t = 0.001 m

    - Final Temperature T_f = 30 C

    - Length of the strip L = 0.1 m

    - coefficient of linear expansion for brass a_b = 19*10^-6

    - coefficient of linear expansion for steel a_s = 13*10^-6

    Find:

    What is the radius of curvature of this arc R?

    Solution:

    - The radius of curvature R in relation to dT and a_b, a_s:

    R = t / dT * (a_b - a_s)

    R = 0.001 / (30-20) * (19-13) * 10^-6

    R = 16.67 m
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