Ask Question
17 December, 14:25

It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s 2. Find the magnitude of acceleration under these new conditions. Answer in units of m/s 2

+1
Answers (1)
  1. 17 December, 14:32
    0
    This Question is not complete

    Complete Question:

    a. A hawk flies in a horizontal arc of radius 11.3 m at a constant speed of 5.7 m/s. Find its centripetal acceleration.

    Answer in units of m/s2

    b. It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s2. Find the magnitude of acceleration under

    these new conditions.

    Answer in units of m/s2

    Answer:

    a. 2.875m/s²

    b. 3.172m/s²

    Explanation:

    a. The formula for centripetal acceleration = (speed²) : radius

    Centripetal acceleration = (5.7m/s) ²: 11.3m

    Centripetal acceleration = 2.875m/s²

    b. Magnitude of acceleration can be calculated by finding the sum of the vectors for the both the centripetal acceleration and the increase in the speed rate.

    Centripetal acceleration (acceleration x) = 2.875m/s²

    Increase in the speed rate (acceleration n) = 1.34m/s²

    Magnitude of acceleration = √a²ₓ + a²ₙ

    =√ (2.875m/s²) ² + (1.34m/s²) ²

    = √ 10.06m/s²

    = 3.172m/s²
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s 2. Find the magnitude of acceleration ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers