A rocket lift off the surface of earth with a constant acceleration of 20 m/sec^2. how fast will the rocket be going 1 min latter?

Question

Anna Russell

Physics

30 August, 17:39

A rocket lift off the surface of earth with a constant acceleration of 20 m/sec^2. how fast will the rocket be going 1 min latter?

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Answers (2)

Know the Answer?

Kaleigh Wood · Answer 1

A = v1-v0/t so v1 = a*t (v0 is o m/s) v1=

20m/s * 60 s = 1200 m/s

Miya Li · Answer 2

"Acceleration of 20 m/s² " means that the rocket is speeding up,

and its speed becomes 20 m/s greater every second.

Since it started out with zero speed, its speed after 1 minute

(60 seconds) is

(20 m/s / s) · (60 s) = 1,200 m/s.