If a spring with a spring constant k = 10 N/m is stretched from its equilibrium position by 0.1 m, and released, what would be the maxi - mum kinetic energy at any time in its motion? Neglect friction.

1. 0.025 J

2. 0.1 J

3. Not enough information given

4. 0.05 J

5. 1 J

0.05J

Explanation:

Since the total energy is conserved I. e the mechanical energy, the energy present in the system are kinetic energy, potential energy and the gravitational potential energy. The expression for this energy is written as

Kinetic Energy=1/2MV^2

Potential Energy=1/2Kx^2

Where K is the spring constant and X is the extension the spring experience.

Gravitational Energy=mgh

Where m=mass, g=gravity constant and h=height

Hence for a spring with spring constant 10N/m and extension 0.1m the potential energy can be calculated as

PE=1/2Kx^2

If we substitute values we arrive at

PE=1/2*10*0.1^2

PE=0.05J