A ball thrown upward near the surface of the Earth with a velocity of 50 m/s will come to rest about 5 seconds later. If the ball were thrown up with the same velocity on Planet X, after 5 seconds it would be still moving upwards at nearly 31 m/s. The magnitude of the gravitational field near the surface of Planet X is what fraction of the gravitational field near the surface of the Earth? Using the MathType functions, be sure to show your work

Question

Denisse

Physics

12 September, 01:51

A ball thrown upward near the surface of the Earth with a velocity of 50 m/s will come to rest about 5 seconds later. If the ball were thrown up with the same velocity on Planet X, after 5 seconds it would be still moving upwards at nearly 31 m/s. The magnitude of the gravitational field near the surface of Planet X is what fraction of the gravitational field near the surface of the Earth? Using the MathType functions, be sure to show your work

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Answers (1)

Know the Answer?

Julio Marquez · Answer 1

19/49

Explanation:

Using v = u + at where v = velocity of ball after 5 s on planet X = 31 m/s, u = initial velocity of ball on planet X = 50 m/s, a = acceleration due to gravity on planet X and t = 5 s

So, 31 = 50 - a * 5 = 50 - 5a

31 - 50 = 5a

-19 = 5a

a = - 19/5 = - 3.8 m/s²

So, the magnitude of a = 3.8 m/s²

So a/g = 3.8/9.8 = 19/49