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2 December, 15:04

A woman walks 237 m in the direction 27.2 east of north, then 335 m directly east. Find the difference between the distance the woman walks and the magnitude of her displacement. (Answer in m.)

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  1. 2 December, 15:14
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    81.1 m

    Explanation:

    X = 237 m 27.2 east of north 237 (Sin27.2 i + Cos 27.2 j)

    X = 108.33 i + 210.8 j

    Y = 335 east = 335 i

    Displacement = X + Y = 108.33 i + 210.8 j + 335 i = 443.33 i + 210.8 j

    (magnitude of displacement) ^2 = 443.33^2 + 210.8^2

    magnitude of displacement = 490.9 m

    Distance traveled = 237 + 335 = 572 m

    Difference in the magnitude of displacement and distance = 572 - 490.9

    = 81.1 m
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