Ask Question
28 January, 15:51

A car is traveling at 52.4 km/h on a flat

highway.

The acceleration of gravity is 9.81 m/s2.

a) If the coefficient of kinetic friction be-

tween the road and the tires on a rainy day is

0.137, what is the minimum distance needed

for the car to stop?

Answer in units of m ... ?

+5
Answers (1)
  1. 28 January, 16:02
    0
    Work is equal to a force over a distance and is equal to the change in kinetic energy, so

    - Fd=ΔKE

    -Fd=1/2m v22 - 1/2m v21

    d = (1/2m v22 - 1/2m v21) / - F

    We know that Ffric=kFnatural and Fnatural=mg so:

    d = (1/2m v22 - 1/2m v21) / - (k∗mg) d = (-1/2 v21) / - (k∗g)

    d = (-1/2 * (14.6m/s) 2) / - (0.137*9.8m/s)

    d = 78.9m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A car is traveling at 52.4 km/h on a flat highway. The acceleration of gravity is 9.81 m/s2. a) If the coefficient of kinetic friction be- ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers