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3 September, 09:16

Light of wavelength 400nm is incident on two slits separated by 1000mm. The interference pattern from the slits is observed from a satellite orbiting 0.4Mm above the Earth. The distance between interference maxima as detected at the satellite is

A. 0.16Mm.

B. 0.16km.

C. 0.16m.

D. 0.16mm.

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Answers (1)
  1. 3 September, 09:42
    0
    We are given:

    λ, Light with a wavelength of 400nm

    w Separation of slits = 1000mm

    L, Distance from the orbit = 0.4Mm

    λ = zw / (mL)

    400x10^-9 = z * 1000x10^-3 / 0.4x10^6 m

    Solve for z, this is the distance between interference maxima as detected at the satellite
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Home » Physics » Light of wavelength 400nm is incident on two slits separated by 1000mm. The interference pattern from the slits is observed from a satellite orbiting 0.4Mm above the Earth. The distance between interference maxima as detected at the satellite is A.
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