When its 75 kW (100 hp) engine is generating full power, a small single-engine airplane with mass 700 kg gains altitude at a rate of 2.5 m>s 1150 m>min, or 500 ft>min2. What fraction of the engine power is being used to make the airplane climb

Question

Haven

Physics

22 February, 22:08

When its 75 kW (100 hp) engine is generating full power, a small single-engine airplane with mass 700 kg gains altitude at a rate of 2.5 m>s 1150 m>min, or 500 ft>min2. What fraction of the engine power is being used to make the airplane climb

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Answers (1)

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Izayah Weber · Answer 1

0.2289

Explanation:

Power required to climb = Fv where F is force and v is soeed. We know that F = mg hence Power, P = mgv and substituting 700 kg for m, 9.81 for g and 2.5 m/s for v then

P = 700*9.81*2.5=17167.5 W = 17.1675 kW

To express it as a fraction of 75 kw then 17.1675/75=0.2289 or 22.89%