A force of 30 N is applied tangentially to the rim of a solid disk of radius 0.14 m. The disk rotates about an axis through its center and perpendicular to its face with a constant angular acceleration of 130 rad/s2. Determine the mass of the disk.

Question

Kujo

Physics

10 November, 10:05

A force of 30 N is applied tangentially to the rim of a solid disk of radius 0.14 m. The disk rotates about an axis through its center and perpendicular to its face with a constant angular acceleration of 130 rad/s2. Determine the mass of the disk.

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Answers (1)

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Anastasia Horton · Answer 1

Answer: 3.27kg

Explanation:

Inertia can be said to be the resistance of an object to a change in its motion. This includes a change in its direction. An object will stay still or keep moving at the same speed and in a straight line, except it is acted upon by an unbalanced external force.

Given F = 30N

r = 0.14m

a = 130rad/s²

Then, T = Fr

T = 30*0.14

T = 4.2Nm

Also, T = inertia * acceleration

Inertia = 4.2/a

Inertia = 4.2/130

Inertia = 0.032

Also, inertia = mr²/2

0.032 = m * (0.14²) / 2

0.032 = m * 0.0098

m = 0.032/0.0098

m = 3.27kg