On Mars, where air resistance is negligible, an astronaut drops a rock from a cliff and notes that the rock falls about d meters during the first t seconds of its fall. Assuming the rock does not hit the ground first, how far will it fall during the first 4t seconds of its fall?

Question

Jax Matthews

Physics

25 December, 06:36

On Mars, where air resistance is negligible, an astronaut drops a rock from a cliff and notes that the rock falls about d meters during the first t seconds of its fall. Assuming the rock does not hit the ground first, how far will it fall during the first 4t seconds of its fall?

+1

Answers (1)

Know the Answer?

June Reynolds · Answer 1

I found the possible answers using deep research:

a) 2d

b) 4d

c) 8d

d) 16d

Ok, so if distance = 1/2 a*t^2 I would look at the first sentence and calculate the acceleration on Mars which is d = (0.5) * a * (1) ^2

a = 2*d meters/sec/sec

The calculation in the first equation is: Distance = (0.5) * 2*d m/s/s * (4*t) ^2.

So im guessing the answer basedon this information to be D.) 16d