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3 February, 22:56

A jet can travel the 6000 km distance between washington,

d. c. and london in 6 hours with the wind. the return trip against the same wind takes 7 hours 30 minutes. find the speed of the jet in still air and the rate of the wind.

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  1. 3 February, 23:25
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    d = r*t is the basic distance equation

    d = 6000 km

    t with the tail wind = 6 hr

    r with the tail wind = speed of the plane + wind speed = s + w

    t with the head wind = 7.5 hr

    r with the head wind = speed of the plane - wind speed = s-w

    (s+w) * 6 = 6000

    (s-w) * 7.5 = 6000

    s + w = 1000

    s - w = 800

    2s = 1800

    s = 900 km/h

    s + w = 1000

    w = 100

    Check the anwer by calculating the return trip.

    (900-100) * 7.5 = 800 * 7.5

    800 * 7.5 = 6000 km

    Answer: The rate of the jet in still air is 900 km/h. The rate of the wind is 100 km/hr.
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