The total energy of a 0.050 kg object travelling at 0.70 c is

A) 2.10 * 107 J

B) 3.06 * 107 J

C) 2.46 * 1015 J

D) 6.30 * 1015 J

E) 8.82 * 1015 J

Question

Blondie

Physics

1 December, 06:19

The total energy of a 0.050 kg object travelling at 0.70 c is

A) 2.10 * 107 J

B) 3.06 * 107 J

C) 2.46 * 1015 J

D) 6.30 * 1015 J

E) 8.82 * 1015 J

+5

Answers (1)

Know the Answer?

Mike Lamb · Answer 1

Would presume the energy as kinetic energy.

E = (1/2) * mv²

But m = 0.05kg, velocity here = 0.70c, where c is the speed of light ≈ 3 * 10⁸ m/s

Ke = (1/2) * mv² = 0.5*0.05 * (0.7 * 3 * 10⁸) ² = 1.1025 * 10¹⁵ Joules

There is no exact match from the options.

The total energy of a 0.050 kg object travelling at 0.70 c isA) 2.10 * 107 JB) 3.06 * 107 JC) 2.46 * 1015 JD) 6.30 * 1015 JE) 8.82 * 1015 J

The total energy of a 0.050 kg object travelling at 0.70 c is

A) 2.10 * 107 J

B) 3.06 * 107 J

C) 2.46 * 1015 J

D) 6.30 * 1015 J

E) 8.82 * 1015 J