A 2.3 kg block is pulled across a friction-free horizontal surface, stretching a spring that has a spring constant of 18 N/m. At the moment it is released, the block accelerates at 0.27 m/s2.

What is the net force that the spring exerts on the block?

N

How far was the spring stretched at the moment it was released?

Question

Khloe Burton

Physics

16 July, 16:55

A 2.3 kg block is pulled across a friction-free horizontal surface, stretching a spring that has a spring constant of 18 N/m. At the moment it is released, the block accelerates at 0.27 m/s2.

What is the net force that the spring exerts on the block?

N

How far was the spring stretched at the moment it was released?

+4

Answers (1)

Know the Answer?

Cornelius Hinton · Answer 1

To find the force on the block, use Newton #1: F = m A

Force = (2.3 kg) x (0.27 m/s²)

Force = (2.3 x 0.27) kg-m/s²

Force = 0.621 Newton

The spring stretches 1 meter when to pull with 18 N of force.

To pull with only 0.621 N of force, it only has to stretch (0.621/18) of a meter. That's 0.0345 meter, or 3.45 cm.