A spring has a constant k = 10.32 N/m and is hung vertically. A 0.400kg mass is suspended from the spring. What is the displacement of the end of the spring due to the weight of the. 400kg mass?

Question

Camden Santos

Physics

15 January, 22:41

A spring has a constant k = 10.32 N/m and is hung vertically. A 0.400kg mass is suspended from the spring. What is the displacement of the end of the spring due to the weight of the. 400kg mass?

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Answers (1)

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Daniella Rios · Answer 1

displacement (x) = 0.003798 meters

Explanation:

from the fact that the string is hung vertically we can deduce that:

Total force acting on the mass = Fs (by spring) + Fg (by gravity)

where

Fs = k*x, x is the displacement ...

Fg = m*g

then:

Ftot = m*a, but a = 0 m / (s^2) because the mass becames stationary.

Ftot = 0

Fs + Fg = 0

by direction, take down as negative.

Fs - Fg = 0

k*x = m*g

x = m*g/k = [ (0.400) (9.8) ] / (10.32)

= 0.3798 meters