An acorn falls from a tree. How fast is the acorn moving after 1.2 seconds?

A. 9.8 m/s

B. 1.2 m/s

C. 8.2 m/s

D. 11.8 m/s

Answer;

D. 11.8 m/s

Explanation;

Using the equation;

v = u + at; such that v is the velocity attained, u is the initial velocity and a is the acceleration;

In our case, acorn falling from a tree is described as free fall aided by gravity;

Therefore, initial velocity is zero, u = 0, and the acceleration is due to gravity, thus, a = 9.8 m/s², t = 1.2 seconds

Thus;

The equation becomes;

v = gt, since; u = 0, and a = g = 9.8 m/s²

v = 9.8 * 1.2

= 11.76 m/s

≈ 11.8 m/s