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4 April, 05:50

A projectile is launched horizontally from a height of 2.2 meters at 32 m/s. How far will it travel horizontally before it hits the ground?

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  1. 4 April, 05:54
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    Total distance covered horizontally S = 21.44 m

    Explanation:

    Given: Height h=2.2 m, Speed Vx=32 m/s

    Required: Total distance covered horizontally S=?

    Sol. we have

    Distance = Speed (horizontal component) * Time

    so we fist calculate time to the ground. so using data

    Initial Velocity Vyi = 0 m/s (Zero Vertical component as launched horizontally).

    g = 9.81 m/s²

    using equation h = Vyi t + 1/2 (at²)

    ⇒ 2.2 m = 0 m/s * t + 4.905 m/s² * t²

    t² = 2.2 m / 4.905 m/s² = 0.4485219164118247 s²

    t = 0.67 s

    Total distance covered horizontally S = 32 m/s * 0.67 s = 21.44 m
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